C++ Program to Check Number is Perfect Square, Armstrong or Prime using While Loop
Write C++ Program to Check Number is Perfect Square, Armstrong or Prime using While Loop
// CPP Program to Check Number is Perfect Square, Armstrong or Prime using While Loop #include <iostream> #include <math.h> using namespace std; int isPerfectSquare(int n) { if (pow((int)sqrt(n), 2) == n) return 1; return 0; } int isArmstrongNumber(int n) { int digits = ceil(log10(n)); int temp = 0, temp2 = n, rem; while (n > 0) { rem = n % 10; temp += pow(rem, digits); n /= 10; } if (temp2 == temp) return 1; return 0; } int isPrime(int n) { int i; for ( i = 2; i < n; i++) { if (n % i == 0) { return 0; } } return 1; } int main(int argc, char *argv[]) { int n, flag = 0; cout << "Enter the number :--> "; cin >> n; if (isPerfectSquare(n)) { flag = 1; cout << "It is a Perfect Square\n"; } if (isArmstrongNumber(n)) { flag = 1; cout << "it is an Armstrong number\n"; } if (isPrime(n)) { flag = 1; cout << "it is a Prime number\n"; } if(flag == 0) { cout << "It's not prime , Armstrong or Perfect Square"; } return 0; }
Output:
Run 1:
Enter the number: 36
It is a perfect square
Run 2:
Enter the number: 89
it is a prime number