C++ Program to Check if Given Number is Perfect Square or Not using For Loop
Write C++ Program to Check if Given Number is Perfect Square or Not using For Loop
// CPP Program to Check if Given Number is Perfect Square or Not using For Loop #include <iostream> #include <math.h> using namespace std; int main() { int n; cout << "Enter the number :--> "; cin >> n; if(pow((int)sqrt(n), 2) == n) { cout << "Perfect Square "; } else { cout << "Not a perfect square"; } return 0; }
Output:
Run 1:
Enter the number :--> 4
Perfect Square
Run 2:
Enter the number :--> 89
Not a perfect square