# Crisp relation – Definition, types and operations

Crisp relation is defined over the cartesian product of two crisp sets. Suppose, A and B are two crisp sets. Then Cartesian product denoted as A×B is a collection of order pairs, such that

A × B = { (a, b)  |  a ∈ A and b ∈ B }

Note:

A × B ≠ B × A

|A × B| = |A| × |B|

A × B provides a mapping from  a ∈ A to b ∈ B

Relation is very useful concept in many fields. It is useful in logic, patter recognition, control system, classification etc.

Crisp relation is set of order pairs (a, b) from Cartesian product A × B such that a ∈ A and b ∈ B. Relations basically represent the mapping of the sets. It defines the interaction or association of variables. The strength of the relationship between ordered pairs of elements in each universe is measured by the characteristic function denoted by χ .

where a value of unity is associated with complete relationship and a value of zero is associated with no relationship, i.e.,

chi_{R}(a,b) = begin{cases} 1 , & if (a,b) in (A times B) \ 0, & if (a,b) notin (A times B) end{cases}

## Example: Crisp realtion

Consider two crisp sets: C = {1, 2, 3} and D = {4, 5, 6}.

• Find Cartesian product of C×D
• Also find relation R over this Cartesian products such that R={(c, d) |  d = c+2, (c, d) ∈ C×D }

Solution:

C × D = { (1, 4), (1, 5), (1, 6),(2, 4), (2, 5), (2, 6),(3, 4), (3, 5), (3, 6) }

From above table, it is easy to infer that, relation R={(2, 4), (3, 5)}

## Representation of crisp relation:

We can represent crisp relation in various ways. One way is to represent it using functional form, which we already have described earlier.

Two other popular representations are shown below:

Let us represent both the relation for the relation R defined over set A and B as,

A = {1, 2, 3}, B = {4, 5, 6}, R = {(2, 4), (3, 5)}

Sagittal / Pictorial Representation:

Matrix Representation:

## Some special realtions:

Let us discuss some special types of relations.

Null Relation: There is no mapping of elements from universe X to universe Y

Complete Relation: All the elements of universe X is mapped to universe Y

Universal Relations: The universal relation on A is defined as UA = A x A = A2

Let A = {0, 1, 2}, then UA = A x A = {(0, 0), (0, 1), (0, 2), (1, 0), (1, 1), (1, 2), (2, 0), (2, 1), (2, 2)}

Identity Relations: The identity relation on A is defined as IA = { (a, a), ∀a ∈ A }

Let A = {0, 1, 2}, then IA = {(0, 0), (1, 1), (2, 2)}

## Operations on crisp relation:

Like operations on crisp sets, we can also perform operations on crisp relations. Suppose, R(x, y) and S(x, y) are the two relations defined over two crisp sets, where x ∈ A and y ∈ B

We will discuss various operations on crisp set for following two crisp relations R and S:

### Union of crisp relation:

R ∪ S = χR ∪ S (x, y) = max( χR(x, y), χS(x, y) )

Union of given relation R and S would be,

### Intersection of crisp relation:

R ∩ S = χR ∩ S (x, y) = min( χR(x, y), χS(x, y) )

Intersection of given relation R and S would be,

### Complement of crisp realtion:

Rc = χRc (x, y)= 1 – χR(x, y)

Intersection of given relation R would be,

### Containment:

R ⊂ S = χR ⊂ S (x, y) = χR(x, y) ≤ χS(x, y)

Relation R is not contained within relation S. Consider the relation T as given below:

Here, χR(x, y) ≤ χT(x, y) , so R is contained within T.

## Cardinality of crisp set:

Cardinality defines the number of elements in the given set. Let A and B be the crisp sets with cardinality n and m, respectively. The cardinality of crisp relation defined over Cartesian product A×B will be n × m

Example:

Let A = (1, 2) and B = {3, 4, 5}

Here, n = |A| = 2 and m = |B| =3, So, n×m=6

The cartesian product of both the set,

A × B={ (1, 3), (1, 4), (1, 5),(2, 3), (2, 4), (2, 5) }

Cardinality of cartesian product is, | A × B | = 6 = n × m

## Composition of crisp realtion:

Composition of relation R and S is denoted as R ∘ S

R ∘ S = {(x, z) | (x, y) ∈ R, and (y, z) ∈ S, ∀y ∈ Y}

Composition of relation is computed in two different ways:

Although, for crisp relation, both methods yields the identical results. For fuzzy relations, it gives different results.

## Test your knowledge:

For the given relations,

Find union, intersection, complement and containment of relation A in B.

### 8 Responses

1. mohammadc says:

Excellent article

• codecrucks says:

2. Rajvi Upadhyay says:

Wonderfully explained with example. Thank you very much for providing better understanding.

• codecrucks says:

Noted with thanks

3. Smita Mahajani says:

Union is Row wise {{1,0,1} , {1,1,1} ,{0,1,1} }

• codecrucks says:

Perfect

4. Smita Mahajani says:

Intersection is {{1,0,0} , {0,0,1} , {0,0,1}} (row wise )

• codecrucks says:

Absolutely correct