C Program to Implement Calculator Using Switch Case
Write C Program to Implement Calculator Using Switch Case
//WAP to implement calculator using Switch case #include <stdio.h> int main() { int n1, n2, x, sum,sub,mul,div; printf("Enter the options as follows: \n1.Addition \n2.Subtraction \n3.Multiplication \n4.Division"); printf("\nYour Option :--> "); scanf("%d", &x); printf("Enter the number 1 :--> "); scanf("%d", &n1); printf("Enter the number 2 :--> "); scanf("%d", &n2); switch(x) { case 1: sum = n1 + n2; printf("%d + %d = %d", n1, n2, sum); break; case 2: sub = n1 - n2; printf("%d - %d = %d", n1, n2, sub); break; case 3: mul = n1 * n2; printf("%d * %d = %d", n1, n2, mul); break; case 4: div = n1 / n2; printf("%d / %d = %d", n1, n2, div); break; default: printf("Please enter the correct input"); break; } return 0; }
Output:
Run 1:
Enter the options as follows:
1.Addition
2.Subtraction
3.Multiplication
4.Division
Your Option :--> 3
Enter the number1 :--> 56
Enter the number2 :--> 2
56 * 2 = 112
Run 2:
Enter the options as follows:
1.Addition
2.Subtraction
3.Multiplication
4.Division
Your Option :--> 1
Enter the number1 :--> 56
Enter the number2 :--> 2
56 + 2 = 58