C Program to Implement Calculator Using Switch Case
Write C Program to Implement Calculator Using Switch Case
//WAP to implement calculator using Switch case
#include <stdio.h>
int main()
{
int n1, n2, x, sum,sub,mul,div;
printf("Enter the options as follows: \n1.Addition \n2.Subtraction \n3.Multiplication \n4.Division");
printf("\nYour Option :--> ");
scanf("%d", &x);
printf("Enter the number 1 :--> ");
scanf("%d", &n1);
printf("Enter the number 2 :--> ");
scanf("%d", &n2);
switch(x)
{
case 1:
sum = n1 + n2;
printf("%d + %d = %d", n1, n2, sum);
break;
case 2:
sub = n1 - n2;
printf("%d - %d = %d", n1, n2, sub);
break;
case 3:
mul = n1 * n2;
printf("%d * %d = %d", n1, n2, mul);
break;
case 4:
div = n1 / n2;
printf("%d / %d = %d", n1, n2, div);
break;
default:
printf("Please enter the correct input");
break;
}
return 0;
}
Output:
Run 1:
Enter the options as follows:
1.Addition
2.Subtraction
3.Multiplication
4.Division
Your Option :--> 3
Enter the number1 :--> 56
Enter the number2 :--> 2
56 * 2 = 112
Run 2:
Enter the options as follows:
1.Addition
2.Subtraction
3.Multiplication
4.Division
Your Option :--> 1
Enter the number1 :--> 56
Enter the number2 :--> 2
56 + 2 = 58