Program to Print All Palindrome Numbers Between 1 and n using For loop

Program to Print All Palindrome Numbers Between 1 and n using For loop

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  • Write a program to Print All Palindrome Numbers Between 1 and n using For loop in Java
  • Write a program to Print All Palindrome Numbers Between 1 and n using For loop in Java Script
  • Write a program to Print All Palindrome Numbers Between 1 and n using For loop in C#

Explanation:

Steps

  1. Input: Accept the upper limit n.
  2. Define a palindrome check function:
    • Reverse the number and compare it to the original.
  3. Iterate from 1 to n:
    • For each number, check if it is a palindrome using the function.
    • If true, print the number.

Program to Print All Palindrome Numbers Between 1 and n using For loop

#include <stdio.h>

int is_palindrome(int num) {
    int original = num, reversed = 0, remainder;

    while (num != 0) {
        remainder = num % 10;
        reversed = reversed * 10 + remainder;
        num /= 10;
    }

    return original == reversed;  // Return true if palindrome
}

int main() {
    int n;

    printf("Enter a number: ");
    scanf("%d", &n);

    printf("Palindrome numbers between 1 and %d are:\n", n);

    for (int num = 1; num <= n; num++) {
        if (is_palindrome(num)) {
            printf("%d ", num);
        }
    }

    return 0;
}

#include <iostream>
using namespace std;

bool is_palindrome(int num) {
    int original = num, reversed = 0, remainder;

    while (num != 0) {
        remainder = num % 10;
        reversed = reversed * 10 + remainder;
        num /= 10;
    }

    return original == reversed;  // Return true if palindrome
}

int main() {
    int n;

    cout << "Enter a number: ";
    cin >> n;

    cout << "Palindrome numbers between 1 and " << n << " are:" << endl;

    for (int num = 1; num <= n; num++) {
        if (is_palindrome(num)) {
            cout << num << " ";
        }
    }

    return 0;
}

def is_palindrome(num):
    original = num
    reversed_num = 0

    while num != 0:
        remainder = num % 10
        reversed_num = reversed_num * 10 + remainder
        num //= 10

    return original == reversed_num  # Return True if palindrome

n = int(input("Enter a number: "))

print(f"Palindrome numbers between 1 and {n} are:")

for num in range(1, n+1):
    if is_palindrome(num):
        print(num, end=" ")

<?php
function is_palindrome($num) {
    $original = $num;
    $reversed = 0;

    while ($num != 0) {
        $remainder = $num % 10;
        $reversed = $reversed * 10 + $remainder;
        $num = (int)($num / 10);
    }

    return $original == $reversed;  // Return true if palindrome
}

$n = (int)readline("Enter a number: ");

echo "Palindrome numbers between 1 and $n are:\n";

for ($num = 1; $num <= $n; $num++) {
    if (is_palindrome($num)) {
        echo "$num ";
    }
}
?>

import java.util.Scanner;

public class PalindromeNumbers {
    public static boolean isPalindrome(int num) {
        int original = num, reversed = 0, remainder;

        while (num != 0) {
            remainder = num % 10;
            reversed = reversed * 10 + remainder;
            num /= 10;
        }

        return original == reversed;  // Return true if palindrome
    }

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        System.out.print("Enter a number: ");
        int n = scanner.nextInt();

        System.out.println("Palindrome numbers between 1 and " + n + " are:");

        for (int num = 1; num <= n; num++) {
            if (isPalindrome(num)) {
                System.out.print(num + " ");
            }
        }

        scanner.close();
    }
}

function isPalindrome(num) {
    let original = num;
    let reversed = 0;

    while (num !== 0) {
        let remainder = num % 10;
        reversed = reversed * 10 + remainder;
        num = Math.floor(num / 10);
    }

    return original === reversed;  // Return true if palindrome
}

let n = parseInt(prompt("Enter a number: "));

console.log(`Palindrome numbers between 1 and ${n} are:`);

for (let num = 1; num <= n; num++) {
    if (isPalindrome(num)) {
        console.log(num);
    }
}

using System;

class Program {
    static bool IsPalindrome(int num) {
        int original = num, reversed = 0, remainder;

        while (num != 0) {
            remainder = num % 10;
            reversed = reversed * 10 + remainder;
            num /= 10;
        }

        return original == reversed;  // Return true if palindrome
    }

    static void Main() {
        Console.Write("Enter a number: ");
        int n = int.Parse(Console.ReadLine());

        Console.WriteLine($"Palindrome numbers between 1 and {n} are:");

        for (int num = 1; num <= n; num++) {
            if (IsPalindrome(num)) {
                Console.Write(num + " ");
            }
        }
    }
}

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