Program to print all Armstrong numbers Between 1 and n using While loop
- Write a program to print all Armstrong numbers Between 1 and n using While loop in C
- Write a program to print all Armstrong numbers Between 1 and n using While loop in C++
- Write a program to print all Armstrong numbers Between 1 and n using While loop in Python
- Write a program to print all Armstrong numbers Between 1 and n using While loop in PHP
- Write a program to print all Armstrong numbers Between 1 and n using While loop in Java
- Write a program to print all Armstrong numbers Between 1 and n using While loop in Java Script
- Write a program to print all Armstrong numbers Between 1 and n using While loop in C#
Explanation:
Logic
What is an Armstrong number?
- A number is an Armstrong number if the sum of its digits raised to the power of the number of digits equals the number itself.
- For example, 153 = 13 + 53 + 33.
Steps:
- Define a function to check if a number is an Armstrong number.
- Start from 1 and keep checking numbers until n
- Print each Armstrong number as it is identified.
Program to print all Armstrong numbers Between 1 and n using While loop
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C
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C++
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Python
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PHP
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JAVA
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Java Script
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C#
#include <stdio.h>
void primeFactors(int num) {
int divisor = 2;
while (num > 1) {
if (num % divisor == 0) {
printf("%d ", divisor);
num /= divisor;
} else {
divisor++;
}
}
}
int main() {
int num;
printf("Enter a number: ");
scanf("%d", &num);
printf("Prime factors of %d are: ", num);
primeFactors(num);
return 0;
}
#include <iostream>
using namespace std;
void primeFactors(int num) {
int divisor = 2;
while (num > 1) {
if (num % divisor == 0) {
cout << divisor << " ";
num /= divisor;
} else {
divisor++;
}
}
}
int main() {
int num;
cout << "Enter a number: ";
cin >> num;
cout << "Prime factors of " << num << " are: ";
primeFactors(num);
return 0;
}
def prime_factors(num):
divisor = 2
while num > 1:
if num % divisor == 0:
print(divisor, end=" ")
num //= divisor
else:
divisor += 1
num = int(input("Enter a number: "))
print(f"Prime factors of {num} are: ", end="")
prime_factors(num)
<?php
function primeFactors($num) {
$divisor = 2;
while ($num > 1) {
if ($num % $divisor == 0) {
echo $divisor . " ";
$num = $num / $divisor;
} else {
$divisor++;
}
}
}
$num = (int)readline("Enter a number: ");
echo "Prime factors of $num are: ";
primeFactors($num);
?>
import java.util.Scanner;
public class PrimeFactors {
public static void primeFactors(int num) {
int divisor = 2;
while (num > 1) {
if (num % divisor == 0) {
System.out.print(divisor + " ");
num /= divisor;
} else {
divisor++;
}
}
}
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print("Enter a number: ");
int num = sc.nextInt();
System.out.print("Prime factors of " + num + " are: ");
primeFactors(num);
sc.close();
}
}
function primeFactors(num) {
let divisor = 2;
while (num > 1) {
if (num % divisor === 0) {
console.log(divisor, " ");
num = Math.floor(num / divisor);
} else {
divisor++;
}
}
}
let num = parseInt(prompt("Enter a number: "));
console.log(`Prime factors of ${num} are:`);
primeFactors(num);
using System;
class Program {
static void PrimeFactors(int num) {
int divisor = 2;
while (num > 1) {
if (num % divisor == 0) {
Console.Write(divisor + " ");
num /= divisor;
} else {
divisor++;
}
}
}
static void Main() {
Console.Write("Enter a number: ");
int num = int.Parse(Console.ReadLine());
Console.Write("Prime factors of " + num + " are: ");
PrimeFactors(num);
}
}