Program to count number of digits in given number using While loop
- Write a program to count number of digits in given number using While loop in C
- Write a program to count number of digits in given number using While loop in C++
- Write a program to count number of digits in given number using While loop in Python
- Write a program to count number of digits in given number using While loop in PHP
- Write a program to count number of digits in given number using While loop in Java
- Write a program to count number of digits in given number using While loop in Java Script
- Write a program to count number of digits in given number using While loop in C#
Explanation:
A for loop can be used to count the number of digits in a given number by continually dividing it by 10 and counting the number of iterations needed to get the number down to 0.
Logic
- Take input for the number (n).
- Initialize a counter variable to 0.
- Use a While loop to repeatedly divide nnn by 10.
- Each time you divide, increment the counter.
- Exit the loop when nnn becomes 0.
- The counter will contain the number of digits in the given number.
Program to count number of digits in given number using While loop
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C
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C++
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Python
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PHP
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JAVA
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Java Script
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C#
#include <stdio.h>
int main() {
int num, count = 0;
printf("Enter a number: ");
scanf("%d", &num);
// Handle negative numbers
if (num < 0) {
num = -num;
}
// Count digits
while (num != 0) {
num /= 10;
count++;
}
printf("Number of digits: %d\n", count);
return 0;
}
#include <iostream>
using namespace std;
int main() {
int num, count = 0;
cout << "Enter a number: ";
cin >> num;
// Handle negative numbers
if (num < 0) {
num = -num;
}
// Count digits
while (num != 0) {
num /= 10;
count++;
}
cout << "Number of digits: " << count << endl;
return 0;
}
num = int(input("Enter a number: "))
count = 0
# Handle negative numbers
if num < 0:
num = -num
# Count digits
while num != 0:
num //= 10
count += 1
print(f"Number of digits: {count}")
<?php
$num = (int)readline("Enter a number: ");
$count = 0;
// Handle negative numbers
if ($num < 0) {
$num = -$num;
}
// Count digits
while ($num != 0) {
$num = (int)($num / 10);
$count++;
}
echo "Number of digits: $count\n";
?>
import java.util.Scanner;
public class CountDigits {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print("Enter a number: ");
int num = sc.nextInt();
int count = 0;
// Handle negative numbers
if (num < 0) {
num = -num;
}
// Count digits
while (num != 0) {
num /= 10;
count++;
}
System.out.println("Number of digits: " + count);
sc.close();
}
}
let num = parseInt(prompt("Enter a number: "));
let count = 0;
// Handle negative numbers
if (num < 0) {
num = -num;
}
// Count digits
while (num != 0) {
num = Math.floor(num / 10);
count++;
}
console.log(`Number of digits: ${count}`);
using System;
class Program {
static void Main() {
Console.Write("Enter a number: ");
int num = int.Parse(Console.ReadLine());
int count = 0;
// Handle negative numbers
if (num < 0) {
num = -num;
}
// Count digits
while (num != 0) {
num /= 10;
count++;
}
Console.WriteLine($"Number of digits: {count}");
}
}