Program to Check if Given Number is Armstrong or Not using For loop
- Write a program to Check if Give Number is Armstrong or Not using For loop in C
- Write a program to Check if Give Number is Armstrong or Not using For loop in C++
- Write a program to Check if Give Number is Armstrong or Not using For loop in Python
- Write a program to Check if Give Number is Armstrong or Not using For loop in PHP
- Write a program to Check if Give Number is Armstrong or Not using For loop in Java
- Write a program to Check if Give Number is Armstrong or Not using For loop in Java Script
- Write a program to Check if Give Number is Armstrong or Not using For loop in C#
Explanation:
Logic
What is an Armstrong number?
- A number is an Armstrong number if the sum of its digits raised to the power of the number of digits equals the number itself.
- For example, 153 = 13 + 53 + 33.
Steps:
- Count the number of digits in the number.
- Calculate the sum of each digit raised to the power of the number of digits.
- Compare the sum to the original number.
Program to Check if Give Number is Armstrong or Not using For loop
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C
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C++
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Python
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PHP
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JAVA
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Java Script
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C#
#include <stdio.h>
#include <math.h>
int main() {
int num, originalNum, remainder, result = 0, n = 0;
printf("Enter a number: ");
scanf("%d", &num);
originalNum = num;
// Find the number of digits
while (originalNum != 0) {
originalNum /= 10;
++n;
}
originalNum = num;
// Calculate the sum of each digit raised to the power of n
while (originalNum != 0) {
remainder = originalNum % 10;
result += pow(remainder, n);
originalNum /= 10;
}
// Check if the number is Armstrong or not
if (result == num)
printf("%d is an Armstrong number.\n", num);
else
printf("%d is not an Armstrong number.\n", num);
return 0;
}
#include <iostream>
#include <cmath>
using namespace std;
int main() {
int num, originalNum, remainder, result = 0, n = 0;
cout << "Enter a number: ";
cin >> num;
originalNum = num;
// Find the number of digits
while (originalNum != 0) {
originalNum /= 10;
++n;
}
originalNum = num;
// Calculate the sum of each digit raised to the power of n
while (originalNum != 0) {
remainder = originalNum % 10;
result += pow(remainder, n);
originalNum /= 10;
}
// Check if the number is Armstrong or not
if (result == num)
cout << num << " is an Armstrong number." << endl;
else
cout << num << " is not an Armstrong number." << endl;
return 0;
}
def is_armstrong(num):
original = num
n = len(str(num)) # Find the number of digits
result = 0
while num > 0:
remainder = num % 10
result += remainder ** n
num //= 10
return result == original # Check if Armstrong
n = int(input("Enter a number: "))
if is_armstrong(n):
print(f"{n} is an Armstrong number.")
else:
print(f"{n} is not an Armstrong number.")
<?php
function is_armstrong($num) {
$original = $num;
$n = strlen((string)$num); // Find the number of digits
$result = 0;
while ($num != 0) {
$remainder = $num % 10;
$result += pow($remainder, $n);
$num = (int)($num / 10);
}
return $result == $original; // Check if Armstrong
}
$n = (int)readline("Enter a number: ");
if (is_armstrong($n)) {
echo "$n is an Armstrong number.\n";
} else {
echo "$n is not an Armstrong number.\n";
}
?>
import java.util.Scanner;
public class ArmstrongNumber {
public static boolean isArmstrong(int num) {
int original = num, n = 0, result = 0;
// Find the number of digits
while (original != 0) {
original /= 10;
++n;
}
original = num;
// Calculate the sum of each digit raised to the power of n
while (original != 0) {
int remainder = original % 10;
result += Math.pow(remainder, n);
original /= 10;
}
return result == num; // Check if Armstrong
}
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("Enter a number: ");
int n = scanner.nextInt();
if (isArmstrong(n)) {
System.out.println(n + " is an Armstrong number.");
} else {
System.out.println(n + " is not an Armstrong number.");
}
scanner.close();
}
}
function isArmstrong(num) {
let original = num;
let n = num.toString().length; // Find the number of digits
let result = 0;
while (num > 0) {
let remainder = num % 10;
result += Math.pow(remainder, n);
num = Math.floor(num / 10);
}
return result === original; // Check if Armstrong
}
let n = parseInt(prompt("Enter a number: "));
if (isArmstrong(n)) {
console.log(`${n} is an Armstrong number.`);
} else {
console.log(`${n} is not an Armstrong number.`);
}
using System;
class Program {
static bool IsArmstrong(int num) {
int original = num, n = 0, result = 0;
// Find the number of digits
while (original != 0) {
original /= 10;
++n;
}
original = num;
// Calculate the sum of each digit raised to the power of n
while (original != 0) {
int remainder = original % 10;
result += (int)Math.Pow(remainder, n);
original /= 10;
}
return result == num; // Check if Armstrong
}
static void Main() {
Console.Write("Enter a number: ");
int n = int.Parse(Console.ReadLine());
if (IsArmstrong(n)) {
Console.WriteLine($"{n} is an Armstrong number.");
} else {
Console.WriteLine($"{n} is not an Armstrong number.");
}
}
}